Senin, 24 September 2012

Induksi Matematika


Buktikan : 2+ 5 + 8 . . . (3n-1) = n ( 3n + 1)/2

I.         n=1
3n-1          = n(3n+1)/2
2               = 2       ( terbukti)
II.      N=k
2+5+8 . . . ( 3k-1)                         = k(3k+1)/2
III.   N=k+1
2+5+8 . . . (3k-1)+( 3(k+1)-1)      = (k+1)(3(k+1)+1)/2
                
K(3k+1)/2            + (3(K+1)-1     =  (k+1)(3(k+1)+1)/2
K(3k+1)/2 + (3k+3-1) (disamakan Penyebut)=  (k+1)(3(k+1)+1)/2
K(3k+1)+6k+4/2                          =  (k+1) (3k+3)+1/2
K(3k+1)+6k+4/2                          =  (k+1) (3k+4)/2
3k2 + k +6k+4/2                           =   3k2 +4k+3k+4/2
3k2 +7k+4/2                                  =  3k2 +7k+4/2

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