Buktikan : 2+ 5 + 8 . . . (3n-1) = n ( 3n +
1)/2
I.
n=1
3n-1 = n(3n+1)/2
2 = 2 ( terbukti)
II.
N=k
2+5+8 . . . ( 3k-1) =
k(3k+1)/2
III.
N=k+1
2+5+8 . . . (3k-1)+( 3(k+1)-1) =
(k+1)(3(k+1)+1)/2
K(3k+1)/2 + (3(K+1)-1 = (k+1)(3(k+1)+1)/2
K(3k+1)/2 + (3k+3-1) (disamakan
Penyebut)=
(k+1)(3(k+1)+1)/2
K(3k+1)+6k+4/2 = (k+1) (3k+3)+1/2
K(3k+1)+6k+4/2 = (k+1) (3k+4)/2
3k2 + k +6k+4/2 =
3k2 +4k+3k+4/2
3k2 +7k+4/2 =
3k2 +7k+4/2
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